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AP EAMCET202316 May 2023Morning ShiftMathematicsStraight LinesActual

A point on the straight line 3 x+5 y=15 which is equidistant from the coordinate axes will lie in

Options

  1. Aeither 1^ st quadrant or 2^ nd quadrant
  2. B4^ th quadrant only
  3. C3^ rd quadrant only
  4. Deither in the 3^ rd or in the 4^ th quadrant

Correct answer

A. either 1^ st quadrant or 2^ nd quadrant

Step-by-step solution

Let P be the point which is equidistant from the coordinate axis. P lies on the line y=x or y=-x . Let us find intersecting point of 3 x+5 y=15 and y=x for this, 3 x+5 x=15 8 x=15 x= 15 8 So, y=x= 15 8 Intersection point of ( 15 8 , 15 8 ) , which is in first quadrant. Now, let us find the intersecting point of 3 x+5 y=15 and y=-x for this 3 x-5 x=15 -2 x=15 x= -15 2 So, y=-x= 15 2 Intersecting point is (- 15 2 , 15 2 ) , which is in 2nd quadrant.

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