Suppose the pairs of straight lines x^2-2 a x y-y^2=0 and x^2-2 b x y-y^2=0 are such that each pair bisects the angles between the other two. Then a b=

Step-by-step solution

Given pairs of straight lines x^ 2-2 a x y and x^22 b x y-y^2=0 bisect the angles between the other two. For x^2-2 a x y-y^2=0 equation of pairs of +1 straight lines which istobe bisected will be x^2+2 x y-a y^2=0 on complaining it with x^2-2 a b x y-y^2=0 We get a=1, b=1 now a, b=-1