AP EAMCET20227 Jul 2022Morning ShiftMathematicsStraight LinesActual
The equation of bisectors of the angle between the lines given by 3 x^2+5 x y+4 y^2=0 is
Options
- Ax^2-y^2- 2 5 x y=0
- Bx^2-y^2+ 2 5 x y=0
- Cx^2-y^2- 1 5 x y=0
- Dx^2-y^2+ 1 5 x y=0
Correct answer
B. x^2-y^2+ 2 5 x y=0
Step-by-step solution
The equation of the bisectors of the angle between the line 3 x^2+5 x y+4 y^2=0 is x^2-y^2 3-4 = x y 5 2 or x^2-y^2=- 2 5 x y i.e. x^2-y^2+ 2 5 x y=0