AP EAMCET202125 Aug 2021Morning ShiftMathematicsStraight LinesActual

The equation of the locus of a point which is equidistant from the points (2,3) and (4,5) is

Options

Ax+y=0
Bx+y=4
Cx+y=7
D4 x+4 y=38

Correct answer

C. x+y=7

Step-by-step solution

Let point P(x, y) which is equidistant from the points (2,3) and (4,5) . array cc & (x-2)^2+(y-3)^2=(x-4)^2+(y-5)^2 & x^2-4 x+4+y^2-6 y+9 & =x^2-8 x+16+y^2-10 y+25 & 4 x+4 y=41-13 & 4(x+y)=28 & x+y=7 array

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