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AP EAMCET202125 Aug 2021Morning ShiftMathematicsStraight LinesActual

The equation obtained by transforming x^2+y^2-6 x+10 y-2=0 to the parallel axis through (3,-5) is

Options

  1. Ax^2+y^2=16
  2. Bx^2+y^2=9
  3. Cx^2+y^2=25
  4. Dx^2+y^2=36

Correct answer

D. x^2+y^2=36

Step-by-step solution

Given equation is aligned x^2+y^2-6 x+10 y-2 & =0 (x-3)^2+(y+5)^2 & =36 aligned The equation obtained by transforming (x-3)^2+(y+5)^2=36 to parallel axis through (3,-5) is Put x-3=h and y+5=k h^2+k^2=36 i.e. x^2+y^2=36

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