If the sum of the distances of a point from two perpendicular lines in a plane is 1 , then its locus is

Step-by-step solution

Let P=(h, k) be any point in the locus let x, y -axes be two perpendicular lines Distance from P(h, k) to X -axis =1 (given) |k|=1 Distance from P(h, k) to Y -axis =1 |h|=1 According to the question, |h|+|k|=1 The locus of point (h, k) is |x|+|y|=1 It is a square Hence, option (2) is correct