AP EAMCET202017 Sep 2020Morning ShiftMathematicsStraight LinesActual
If (p ) and (q ) are lengths of the perpendiculars from origin to the lines (x ( )+y cosec ( )=k ) and (x ( )-y ( )=k (2 ) ) respectively, then
Options
- A(p^2+4 q^2=k^2 )
- B(4 p^2+q^2=k^2 )
- C(p^2+q^2=4 k^2 )
- D(p^2+q^2=k^2 )
Correct answer
B. (4 p^2+q^2=k^2 )
Step-by-step solution
(p= |0+0-k| ^2 + cosec ^2 , q= |0-0-k ^2 | ^2 + ^2 ) ( p^2= k^2 ^2 + cosec ^2 , q^2=k^2 ^2 2 ) ( p^2= k^2 1 ^2 + 1 ^2 , q^2=k^2 ^2 2 ) ( p^2=k^2 ^2 ^2 , q^2=k^2 ^2 2 ) ( p^2= k^2 4 ^2 2 , q^2=k^2 ^2 2 ) So, (p^2+ q^2 4 = k^2 4 4 p^2+q^2=k^2 )