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AP EAMCET201923 Apr 2019Morning ShiftMathematicsStraight LinesActual

The intercept form of the equation of the straight line passing through the point ((4,-3) ) and perpendicular to the line passing through the points ((1,1) ) and ((2,3) ) is

Options

  1. A( x-4 1 = y+3 1 )
  2. B( x -2 + y -1 =1 )
  3. C( x 8 - y 6 =1 )
  4. D( x 1 + y 1 =1 )

Correct answer

B. ( x -2 + y -1 =1 )

Step-by-step solution

Let ( aligned A & =(4,-3) B & =(1,1) C & =(2,3) aligned ) Slope of (B C= 3-1 2-1 =2 ) ( ) Slope of required line (=- 1 2 ) [ ( ) Lines are perpendicular] ( ) Equation of line passing through (A(4,-3) ) and having slope is ( -1 2 ) ( array rlrl y-y₁ & =m (x-x₁ ) & y+3 = -1 2 (x-4) & 2 y+6 =-x+4 & x+2 y+2 =0 & x+2 y =-2 & x -2 + y -1 =1[ divided by -2 on both sides ] array ) ( ) Hence, option (b) is correct.

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