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AP EAMCET201920 Apr 2019Evening ShiftMathematicsStraight LinesActual

The centroid of the triangle formed by the lines x+y-1=0, x-y-1=0, x-3 y+3=0 is

Options

  1. A( 4 3 , 1 )
  2. B( -4 3 , 1 )
  3. C( 8 3 , 3 )
  4. D( -8 3 , 3 )

Correct answer

A. ( 4 3 , 1 )

Step-by-step solution

Point of intersection of lines x+y-1=0 and x-y-1=0 is A(1,0) . Similarly, point of intersection of lines x-y-1=0 and x-3 y+3=0 is B(3,2) , and point of intersection of lines x-3 y+3=0 and x+y-1=0 is C(0,1) . Now, centroid of A B C is ( 1+3+0 3 , 0+2+1 3 ) = ( 4 3 , 1 )

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