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AP EAMCET201920 Apr 2019Morning ShiftMathematicsStraight LinesActual

The equation of the line through the point of intersection of the lines (3 x-4 y+1=0 ) and (5 x+y-1=0 ) and making equal non-zero intercepts on the coordinate axes is

Options

  1. A(2 x+2 y=3 )
  2. B(23 x+23 y=6 )
  3. C(23 x+23 y=11 )
  4. D(2 x+2 y=7 )

Correct answer

C. (23 x+23 y=11 )

Step-by-step solution

We have, equation of the line through the point of intersection of the lines (3 x-4 y+1=0 ) and (5 x+y-1=0 ) is ( array lc & (3 x-4 y+1)+ (5 x+y-1)=0 & (3+5 ) x+( -4) y=( -1) & x -1 3+5 + y -1 -4 =1 array ) According to given information ( array rlrl -1 3+5 & = -1 -4 and 1 & -4 =5 +3 & 4 =-7 =- 7 4 array ) So, equation of required line is ( array rlrlrl & (3- 35 4 ) x+ (- 7 4 -4 ) y & = (- 7 4 -1 ) & - 23 4 x- 23 4 y =- 11 4 & 23 x+23 y =11 array ) Hence, option (3) is correct.

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