AP EAMCET201822 Apr 2018Evening ShiftMathematicsStraight LinesActual
If the straight line L 3 x+4 y-k=0 cuts the line segment joining the points P(2,-1) and Q(1,1) in the ratio 4: 1 , then the equation of the line parallel to the line y=x and concurrent with the lines P Q and L=0 is
Options
- A2 x-2 y+7=0
- Bx-y+1=0
- C5 x-5 y-3=0
- Dy=x+3
Correct answer
C. 5 x-5 y-3=0
Step-by-step solution
Point of intersection of given line L=0 and line segment P Q is R ( (4 1)+(1 2) 5 , (4 (1))+(1 (-1)) 5 )=R ( 6 5 , 3 5 ) Now, point R on the Line L=0 , So, 18 5 + 12 5 -k=0 k=6 Now, equation of Line concurrent with the lines L=0 and P Q is Line Eq. (i) is parallel to the Line y=x , so aligned - 3+2 4+ & =1 & =- 7 3 . aligned Equation of required line is 5 x-5 y-3=0