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AP EAMCET2014MathematicsStraight Lines

The equation of a straight line, perpendicular to 3 x-4 y=6 and forming a triangle of area 6 sq. units with coordinate axes, is

Options

  1. Ax-2 y=6
  2. B4 x+3 y=12
  3. C4 x+3 y+24=0
  4. D3 x+4 y=12

Correct answer

B. 4 x+3 y=12

Step-by-step solution

Given equation of line is 3 x-4 y=6 Perpendicular to above line is 4 x+3 y=k Area of O A B = 1 2 O A O B aligned & & 6 & = 1 2 k 4 k 3 & & 6 & = k^2 24 & & k^2 & =144 & & k & = 12 aligned Required equation of line is 4 x+3 y= 12

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