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AP EAMCET2012MathematicsStraight Lines

The distance between the parallel lines given by (x+7 y)^2+4 2 (x+7 y)-42=0 is

Options

  1. A4 5
  2. B4 2
  3. C2
  4. D10 2

Correct answer

C. 2

Step-by-step solution

Given equation is (x+7 y)^2+4 2 (x+7 y)-42=0 Put x+7 y=t aligned & t^2+4 2 (t)-42=0 & t= -4 2 32+168 2 & = -4 2 10 2 2 & =3 2 ,-7 2 & x+7 y=3 2 & aligned and x+7 y=-7 2 x+7 y-3 2 =0 and x+7 y+7 2 =0 Distance between parallel lines = |7 2 +3 2 | 1^2+7^2 = 10 2 5 2 =2

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