AP EAMCET2010MathematicsStraight Lines
The image of the point (4,-13) with respect to the line 5 x+y+6=0 is
Options
- A(-1,-14)
- B(3,4)
- C(1,2)
- D(-4,13)
Correct answer
A. (-1,-14)
Step-by-step solution
Since, Q is the mid point of P P^ , then Q= ( x₁+4 2 , y₁-13 2 ) Also Q lies on the A B , then 5 ( x₁+4 2 )+ ( y₁-13 2 )+6=05 x₁+20+y₁-13+12=05 x₁+y₁+19=0 (i) Since, line P P^ is perpendicular to A B , then (Slope of A B) ( . Slope of .P P^ )=-1(-5) ( y₁+13 x₁-4 )=-15 y₁+65=x₁-4x₁-5 y₁-69=0 (ii) Solving Eqs. (i) and (ii), we get array r 25 x₁+5 y₁+95=0 x₁-5 y₁-69=0 26 x₁+26=0 array x₁=-1 From Eq.(ii) 5 y₁=-1-695 y₁=-70y₁=-14 So, image of the point p with respect to A B is (-1,-14)