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AP EAMCET2009MathematicsStraight Lines

The equation of the straight line perpendicular to the straight line 3 x+2 y=0 and passing through the point of intersection of the lines x+3 y-1=0 and x-2 y+4=0 is

Options

  1. A2 x-3 y+1=0
  2. B2 x-3 y+3=0
  3. C2 x-3 y+5=0
  4. D2 x-3 y+7=0

Correct answer

D. 2 x-3 y+7=0

Step-by-step solution

The point of intersection of lines x+3 y-1=0 and x-2 y+4=0 is (-2,1) . Let equation of line perpendicular to the given line is 2 x-3 y+ =0 . Since, it passes through (-2,1) . array lc & 2(-2)-3(1)+ =0 & =7 & Required line is 2 x-3 y+7=0 array

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