The perpendicular distance from origin to the plane x + 2y − 2z + 5 = 0 equals ………units.

Step-by-step solution

Given, plane is x + 2y − 2z + 5 = 0 Perpendicular distance from (x₁, y₁, z₁ ) to plane a x+b y+c z+d=0 is P= | a x₁+b y₁+c z₁+d a^2+b^2+c^2 | P= | 0+0+0+5 1^2+2^2+(-2)^2 | P= 5 3