AP EAMCET202120 Aug 2021Morning ShiftMathematicsThree Dimensional GeometryActual
Let a → = i ^ and b → = j ^ is the point of intersection of the lines r → × a → = b → × a → and r → × b → = a → × b → is
Options
- Ar → = i ^ + j ^
- Br → = i ^ - j ^
- Cr → = k ^
- Dr → = 2 i ^ + j ^
Correct answer
A. r → = i ^ + j ^
Step-by-step solution
Given, r → × a → = b → × a → ∴ r → - b → × a → = 0 The Equation of line is, r → = b → + p a → Similarly, for second line r → × b → = a → × b → The Equation of line is r → = b → + q a → As they both intersect b → + q a → = b → + p a → On comparing the coefficients we get p = q = 1 Hence, the equation of line is r → = b → + a → ⇒ r →