AP EAMCET202022 Sep 2020Evening ShiftMathematicsThree Dimensional GeometryActual
The Cartesian equation of the line passing through the point (-1,3,-2) and perpendicular to the lines x 1 = y 2 = z 3 and x+2 -3 = y-1 2 = z+1 5 is
Options
- Ax-1 2 = y+3 7 = z-2 4
- Bx-1 -2 = y+3 -7 = z-2 -4
- Cx+1 2 = y+3 7 = z+2 4
- Dx+1 2 = y-3 -7 = z+2 4
Correct answer
D. x+1 2 = y-3 -7 = z+2 4
Step-by-step solution
P=(-1,3,-2) Let dr 's or required line be (a, b, c) Dr's of line x 1 = y 2 = z 3 are (1,2,3) Given that required line perpendicular to above line a₁ a₂+b₁ b₂+c₁ c₂=0 a+2 b+3 c=0 Similarly required line perpendicular to x+2 -3 = y-1 2 = z+1 5 -3 a+2 b+5 c=0 On solving Eqs. (i) and (ii), we get aligned & a 10-6 = b -9-5 = c 2+6 & a 2 = b -7 = c 4 & aligned Required line is passing through (-1,3,-2) and having dr's (2,-7,4) x+1 2 = y-3 -7 = z+2 4