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AP EAMCET201921 Apr 2019Morning ShiftMathematicsThree Dimensional GeometryActual

If the two lines x-1 2 = y+1 3 = z-1 4 and x-3 1 = y-k 2 = z 1 have a point in common, then k=

Options

  1. A2 9
  2. B- 2 9
  3. C9 2
  4. D0

Correct answer

C. 9 2

Step-by-step solution

Given line is x-1 2 = y+1 3 = z-1 4 = So, (x, y, z) is (2 +1,3 -1,4 +1) and this point is lies on given line. This point also lies on line. x-3 1 = y-k 2 = z 1 So, this point satisfies equation array rlrl & & 2 +1-3 1 & = 3 -1-k 2 = 4 +1 1 & & 2 -2 1 & = 4 +1 1 & 2 -2 & =4 +1 & & 2 & =-3 & & & =- 3 2 array Now, 3 -1-k 2 = 2 -2 1 3 - 3 2 -1-k 2 = 2 - 3 2 -2 1 array ll & - 9 2 -1-k 2 = -3-2 1 - 11 2 -k=-10 & - 11 2 +10=k k= 9 2 array

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