Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201920 Apr 2019Morning ShiftMathematicsThree Dimensional GeometryActual

The plane (3 x+4 y+6 z+7=0 ) is rotated about the line ( r =( i +2 j -3 k )+t(2 i -3 j + k ) ) until the plane passes through origin. The equation of the plane in the new position is

Options

  1. A(x+y+z=0 )
  2. B(6 x+3 y-4 z=0 )
  3. C(4 x-5 y-2 z=0 )
  4. D(x+2 y+4 z=0 )

Correct answer

A. (x+y+z=0 )

Step-by-step solution

Equation of plane passes through the origin and containing the line ( aligned & r =( i +2 j -3 k )+t(2 i -3 j + k ) is & ( r -0) [( i +2 j -3 k ) (2 i -3 j + k )]=0 & r [ i (2-9)- j (1+6)+ k (-3-4)]=0 & r (-7 i -7 j -7 k )=0 & r ( i + j + k )=0 or x+y+z=0 aligned ) Hence, option (1) is correct.

Practice Three Dimensional Geometry on Quantrex Academy →

More from Three Dimensional Geometry

The circum radius of the triangle formed by the points (2,-1,1),(1,-3,-5) and (3,-4,-4) is 2025Let A (2,3,5), B (-1,3,2), C ( , 5, ) be the vertices of ABC . If the median through the vertex A is equally inclined to the coordinate axes, then 2025Equation of the plane passing through the origin and perpendicular to the planes x+2 y-z=1 and 3 x-4 y+z=5 is 2025If the line joining the points i +2 j and j -2 k intersects the plane passing through the points 2 i - j , 2 j +3 k and k -2 i at r , then r ( i + j + k )= 2025The vector equation of a plane passing through the line of intersection of the planes r ( i -2 k )=3, r (2 j + k )=5 and the point i +2 j +3 k is 2025The points A (-1,2,3), B (2,-3,1), C (3,1,-2) 2025The direction cosines of the line making angles 4 , 3 and (0 < < 2 ) respectively with X , Y and Z axes are 2025If the equation of the plane passing through the point (3,2,5) and perpendicular to the planes 2 x-3 y+5 z=7 and 5 x+2 y-3 z=11 is x+b y+c z+d=0 , then 2 b+3 c+d= 2025 Full Three Dimensional Geometry list All AP EAMCET PYQs