AP EAMCET201824 Apr 2018Morning ShiftMathematicsTrigonometric EquationsActual
If A is in the third quadrant and A= 7 3 , then 18-16 ^2 A 2 -32 A 2 5 A 2 =
Options
- A-6
- B11
- C5
- D10
Correct answer
B. 11
Step-by-step solution
aligned & 18-16 ^2 A 2 -32 A / 2 5 A / 2 & =18-8 (2 ^2 A 2 )-16 (2 A 2 5 A 2 ) & =18-8(1- A)-16 ( ( 5 A 2 - A 2 )- ( 5 A 2 + A 2 ) ) & [ ascos (A-B)- (A+B)=2 A B & =18-8+8 A-16 2 A+16 3 A & =10+8 A-16 [2 ^2 A-1 ] & +16 [4 ^3 A-3 2 A ] aligned [as 3 A=4 ^3 A-3 A, 2 A=2 ^2 A-1 ] Now, A lies in third quadrant and A= 7 3 aligned & A= -3 4 & =10+8 ( -3 4 )-16 [2 ( 9 16 )-1 ] & +16 [4 ( -27 64 )-3 ( -3 4 ) ] aligned aligned & =10-6-16 1 8 +16 ( -27 16 + 9 4 ) & =10-6-2+16 9 16 =2+9=11 . aligned