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AP EAMCET2010MathematicsTrigonometric Equations

The period of ( - 1 3 ^3 ) ( 1 3 - ^2 )⁻¹ where ^2 1 3 is

Options

  1. A3
  2. B2 3
  3. C2

Correct answer

A. 3

Step-by-step solution

( - 1 3 ^3 ) ( 1 3 - ^2 )⁻¹ where, ^2 1 3 = ( - 1 3 ^3 ) ( 1 3 - ^2 ) = 3 (3 - ^3 ) 3 (1-3 ^2 ) = 3 3 = ( 3 - ^3 1-3 ^2 )= ( +3 )= 3 ( 3 + ) So, the period of the given function is 3 .

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