AP EAMCET2002MathematicsTrigonometric Equations
If a point (x, y)=( + , - ) , then the locus of (x, y) is
Options
- A(x^2 y )^ 2 / 3 + (x y^2 )^ 2 / 3 =1
- Bx^2-y^2=4 x y
- Cx^2-y^2=12 x y
- D(x^2-y^2 )^2=16 x y
Correct answer
D. (x^2-y^2 )^2=16 x y
Step-by-step solution
Given that, array cc & + =x & - =y & = x+y 2 , = x-y 2 & ( x+y 2 ) ( x-y 2 )= & x^2-y^2=4 ( ^2 )=4 ( 1- ^2 ) & x^2-y^2=4( - ) & (x^2-y^2 )^2=16 ( ^2+ ^2 -2 ) & (x^2-y^2 )^2=16 (1+ ^2 +1- ^2 -2 ) & (x^2-y^2 )^2=16 ( ^2 - ^2 ) & (x^2-y^2 )^2=16 x y array