Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET202123 Aug 2021Evening ShiftMathematicsTrigonometric Ratios & IdentitiesActual

Minimum value of 5 ^2 + 9 ^2 +4 ^2 is

Options

  1. A24
  2. B22
  3. C32
  4. D28

Correct answer

B. 22

Step-by-step solution

5 ^2 + 9 ^2 +4 ^2 =5 ^2 +9 ^2 +4 (1+ ^2 ) [ ^2 x=1+ ^2 x ]=9 ^2 +9 ^2 +4 Since, we know that A M G M 9 ^2 +9 ^2 2 9 ^2 9 ^2 9 ^2 +9 ^2 9 2 9 ^2 +9 ^2 18 9 ^2 +9 ^2 +4 18+4=22 Hence, minimum values =22

Practice Trigonometric Ratios & Identities on Quantrex Academy →

More from Trigonometric Ratios & Identities

If x+ x= 1 2 and 0 < x < , then x= 2025If A and B are acute angles satisfying 3 ^2 A+2 ^2 B=4 and 3 A B = 2 B A , then A+2 B= 2025In a ABC , if ^2 ~B = A and 2 ^2 ~A =3 ^2 ~B , then the triangle is 202512 2 12 3 12 4 12 5 12 6 12 = 2025If ( 4 + )= ^3 ( 4 + ) , then ( + ) ( - )= 2025If A+B+C+D=2 , then A+ B+ C+ D= 2025(4 ^2 20 -1 ) (4 ^2 3 20 -1 ) (4 ^2 5 20 +1 ) (4 ^2 7 20 -1 ) (4 ^2 9 20 -1 )= 2025If A and B are the values such that (A+B) and (A-B) are not odd multiples of 2 and 2 (A+B)=3 (A-B) , then A A= 2025 Full Trigonometric Ratios & Identities list All AP EAMCET PYQs