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AP EAMCET202123 Aug 2021Evening ShiftMathematicsTrigonometric Ratios & IdentitiesActual

_ x 0 (x)+4 (2 x)-3 (3 x) x^2 (x) is equal to

Options

  1. A8
  2. B-8
  3. C16
  4. D-16

Correct answer

D. -16

Step-by-step solution

_ x 0 x+4 2 x-3 3 x x^2 x = _ x 0 [ x+4 ( 2 x 1- ^2 x )-3 ( 3 x- ^3 x 1-3 ^2 x ) x^2 x ]= _ x 0 [ x 1+ 8 1- ^2 x - (9-3 ^2 x . 1-3 ^2 x x^2 x ] aligned & = _ x 0 [ -16 ^2 x x^2 (1- ^2 x ) (1-3 ^2 x ) ] & =-16 _ x 0 ( x x )^2 _ x 0 1 (1- ^2 x ) (1-3 ^2 x ) & =-16(1)^2 1 1 1 =-16 aligned

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