AP EAMCET202120 Aug 2021Evening ShiftMathematicsTrigonometric Ratios & IdentitiesActual
If A + B + C = 3 π 2 , then cos 2 A + cos 2 B + cos 2 C =
Options
- A1 - 4 sin A sin B sin C
- B1 + 4 sin A sin B sin C
- C1 - 2 sin A sin B sin C
- D1 + 2 sin A sin B sin C
Correct answer
A. 1 - 4 sin A sin B sin C
Step-by-step solution
cos 2 A + cos 2 B + cos 2 C = 2 cos A + B cos A - B + cos 2 C ∵ cos C + cos D = 2 cos C + D 2 cos C - D 2 = 2 cos 3 π 2 - C cos A - B + 1 - 2 sin 2 C ∵ A + B + C = 3 π 2   &   cos 2 θ = 1 - 2 sin 2 θ = 1 - 2 sin C cos A - B - 2 sin 2 C = 1 - 2 sin C cos A - B + sin 3 π 2 - A + B ∵ A + B + C = 3 π 2 = 1 - 2 sin C cos A - B - cos A + B = 1 - 4 sin A sin B sin C ∵ cos C - cos D = 2 sin C + D 2 sin D - C 2