AP EAMCET202318 May 2023Evening ShiftMathematicsVector AlgebraActual
If a =t b where t < 0 is a scalar, then
Options
- Aa , b are like vectors and | a |>| b |
- Ba , b are unlike vectors and | a |>| b |
- Ca , b are like vectors and | a | < | b |
- Da , b are unlike vectors and either | a | | b | or | a | < | b |
Correct answer
D. a , b are unlike vectors and either | a | | b | or | a | < | b |
Step-by-step solution
Given a =t b where t < 0 is a scalar t is negative. t =- k for some k Z ⁺ So, we have a =-k b ......(i) a , b are unlike vectors. Taking mod on both sides of eqn. (i), we get | a |=|-k b | | a |=|k|| b | If 0 < |k| < 1 then | a | < | b | And if | k | 1 then | a | | b |