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AP EAMCET20226 Jul 2022Morning ShiftMathematicsVector AlgebraActual

If A B C D is a cyclic quadrilateral with R as the radius of the circumcircle and ( AB )^2+(C D)^2=4 R^2 then

Options

  1. Ab c - a d =0
  2. Ba c - b d =0
  3. Ca b + c d =0
  4. Da c + b d =0

Correct answer

C. a b + c d =0

Step-by-step solution

We know that if A B C D is a cyclic quadrilateral with R as the radius of the circumcircle and AB ^2+ CD ^2=4 R ^2 ABCD is a rhombus. aligned & AOB =90^ and COD =90^ & a b =0 and c d =0 aligned So. a b + c d =0

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