NEET2019ZoologyEvolutionActual
A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the Population?
Options
- A0.36(AA); 0.48(Aa); 0.16(aa)
- B0.16(AA); 0.24(Aa); 0.36(aa)
- C0.16(AA); 048(Aa); 0.36(aa)
- D0.16(AA); 0.36(Aa); 0.48(aa)
Correct answer
C. 0.16(AA); 048(Aa); 0.36(aa)
Step-by-step solution
According to the Hardy-Weinberg principle: Frequency of dominant allele (A) = p =0.4 Frequency of recessive allele (a) = q Sum total of all the allelic frequencies is 1, i.e. p+q = 1 ⇒ 0.4 + q = 1 ⇒ q = 0.6 Frequency of AA individuals = p × p = p 2 = (0.4) 2 = 0.16 Frequency of aa individuals = q × q = q 2 = (0.6) 2 = 0.36 Frequency of Aa individuals = 2pq = 2(0.4)(0.6) = 0.48