In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa, and the remaining 160 to aa, Based on this data, the frequency of allele A in the population is:

Step-by-step solution

According to Hardy – Weinberg principle: Frequency of dominant allele (A) = p Frequency of recessive allele (a) = q Frequency of AA individuals = p × p = p 2 Frequency of aa individuals = q × q = q 2 Frequency of Aa individuals = 2pq Total population = 1000 Frequency of AA individuals = p × p = p 2 = 360/1000 = 0.36 Frequency of dominant allele (A) = p = 0.6