If the position vectors of the vertices of a triangle are 2 i - j + k , i -3 j -5 k and 3 i -4 j -4 k , then the triangle is

Step-by-step solution

Let A =2 i - j + k , B = i -3 j -5 k C =3 i -4 j -4 k A B=- i -2 j -6 k , BC =2 i - j + k and aligned & C A =- i +3 j + k & a=| B C |= 4+1+1 = 6 & b=| C A |= 1+9+25 = 35 & c=| A B |= 1+4+36 = 41 aligned Now, c^2=a^2+b^2 aligned 41 & =6+35 & =41=41 aligned It is right angled triangle