An amplitude modulate wave is represented by 10 [1+0.6 (40 10^3 t ) ] (4 10^6 t ) volt where t is in seconds. Then the ratio of the upper to the lower side band frequencies is

Step-by-step solution

An Amplitude modulate wave is represented by C _ m =10 [1+0.6 (40 10^3 t ) ] (4 10^6 t ) V Compair with aligned & C_m=A_C [1+ A_m A_c _m ] _c t v & A_m A_c =0.6 _m=40 10^3 _c=4 10^6 aligned f_m= 40 10^3 2 H z ; f_c= 4 10^6 2 H z aligned & Ratio = Upper side bond Lower side bond = f_c+f_m f_c-f_m = 4 10^6+40 10^3 4 10^6-40 10^3 & Ratio = 4040000 3960000 = 101 99 aligned