A radio receiver antenna that is 4 ~m long is oriented along the direction of the electromagnetic wave and it receives a signal of intensity 8 10⁻¹⁶ Wm ⁻² . The maximum instantaneous potential difference across the two ends of the antenna is

Step-by-step solution

Given that, length of antenna, l=4 ~m Intensity of signal, I=8 10⁻¹⁶ ~W / m ^2 Using, I= 1 2 ₀ c E₀^2 E₀= 2 I ₀ c By substituting the values, we get E₀= 2 8 10⁻¹⁶ 8.85 10⁻¹² 3 10^8 =0.776 10⁻⁶ ~V / m Now, maximum potential difference, V₀=E₀ l=4 0.776 10⁻⁶ ~V =3.1 V