Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201921 Apr 2019Morning ShiftPhysicsCommunication SystemActual

A transmitting antenna of height 20 ~m and the receiving antenna of height h are separated by a distance of 40 ~km for satisfactory communication in line of sight (Los) mode. Then the value of h is (Give, radius of earth is 6400 ~km .)

Options

  1. A40 m
  2. B45 m
  3. C30 m
  4. D25 m

Correct answer

B. 45 m

Step-by-step solution

Given, height of transmitting antenna h_T=20 ~m , distance of LOS, d_m=40 ~km As maximum distance of line of sight mode d_m= 2 R h_T + 2 R h_R putting the given values, we get aligned 40= & 2 6.4 10^3 20 10⁻³ & + 2 6.4 10^3 h_R 10⁻³ 40 & =16+ 2 6.4 10^3 10⁻³ h_R 2 6.4 h_T & =24 24 h_T & =45 ~m aligned Hence, the correct option is (b).

Practice Communication System on Quantrex Academy →

More from Communication System

In amplitude modulation, if a message signal of 5 kHz is modulated by a carrier wave of frequency 900 kHz, then the frequencies of the side bands are 2025The heights of tansmitting and receiving antennas are respectively 1 20000 and 1 80000 times the radius of the earth. The maximum distance between these two antennas for satisfacto 2025The layer of the atmosphere that reflects low frequency (LF) electromagnetic waves during day time only is 2025If the ratio of the maximum and minimum amplitudes of an amplitude modulated wave is 7: 3 , then the modulation index is 2025If the maximum and minimum amplitudes of a modulated wave are 25 V and 5 V respectively, then the modulation index is 2025Ionosphere acts as a reflector for the frequency range of 2025If in an amplitude modulated wave, the maximum amplitude is 14 V and the modulation index is 0.4, then the amplitude of the carrier wave is 2025For transmitting a signal of frequency 1000 kHz, the minimum length of the antenna is 2025 Full Communication System list All AP EAMCET PYQs