If the average power per unit area delivered by an electromagnetic wave is 9240 W m - 2 , then the amplitude of the oscillating magnetic field in EM wave is

Step-by-step solution

Average power per unit area of an electromagnetic wave is given by I = c B m a x 2 2 μ 0 , here, c is speed of light in vacuum and μ 0 is permeability of free space. Now, the amplitude of the oscillating magnetic field is B m a x = 2 μ 0 I c = 2 × 4 π × 10 - 7 × 9240 3 × 10 8 = 8 . 79 × 10 - 6   T = 8 . 8   μT