Suppose that the electric field of an electromagnetic wave in vacuum is E = (3.1 NC ⁻¹ ) [1.8 rad . m ⁻¹ ) .y+ (5.4 10^6 rad s ⁻¹ ) t ] i . What is the wavelength ?

Step-by-step solution

Given that, equation of electric field of an electromagnetic wave in vacuum, E = (3.1 NC ⁻¹ ) [ (1.8 rad m ⁻¹ ) y+ (5.4 10^6 rad s ⁻¹ ) t ] i We know that, general equation E =E₀ [k y+w t] i Comparing Eqs. (i) and (ii), we get Propagation constant, k=1.8 rad / m i.e., 2 =1.8 = 2 1.8 =3.49 ~m Hence, wavelength of electromagnetic wave is 3.49 ~m .