AP EAMCET201922 Apr 2019Morning ShiftPhysicsElectromagnetic WavesActual
Match the following List-I with List-II. ( array cccc & List-I & & List-II A. & E d A & (i) & 0 B. & B d A & (ii) & - d _B d t C. & E d l & (iii) & Q E₀ D. & B d l & (iv) & ₀ (i_c+i_d ) array )
Options
- A( array cccc A & B & C & D (iii) & (ii) & (i) & (iv) array )
- B( array cccc A & B & C & D (iv) & (i) & (iii) & (ii) array )
- C( array cccc A & B & C & D (iii) & (i) & (ii) & (iv) array )
- D( array cccc A & B & C & D (iii) & (i) & (iv) & (ii) array )
Correct answer
C. ( array cccc A & B & C & D (iii) & (i) & (ii) & (iv) array )
Step-by-step solution
( A ) III According to Gauss's law, total electric flux passing through a closed surface is equal to ( 1 ₀ ) times the total charge enclosed within the surface. i.e., ( = E . d A = Q ₀ ) ( B I ), According to gauss' law of magnetism, total magnetic flux passing through a bar magnet around its enclosed surface is zero because the magnetic lines of forces emerging from North-pole is equal to magnetic lines of force entering into South direction. i.e., ( B. d A=0 ) ( C ) II, The electromotive force in a wire is the li