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AP EAMCET202423 May 2024Morning ShiftPhysicsGravitationActual

The time period of revolution of a satellite close to planet's surface is 80 minutes. The time period of another satellite which is at a height of 3 times the radius of the planet from surface is

Options

  1. A64 minutes
  2. B640 minutes
  3. C320 minutes
  4. D240 minutes

Correct answer

B. 640 minutes

Step-by-step solution

By Kepler's period law, aligned & T ^2 r ^3 & ( ~T ₂ ~T ₁ )^2= ( r ₂ r ₁ )^3= ( R +3 R R )^3=64 & ~T ₂ ~T ₁ =8 ~T ₂=8 ~T ₁=8 80=640 ~min aligned

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