The acceleration due to gravity at a height of 6400 km from the surface of the earth is 2.5 ~ms ⁻² . The acceleration due to gravity at a height of 12800 km from the surface of the earth is (Radius of the earth =6400 ~km )

Step-by-step solution

g ₁=2.5 ~m / s ^2, ~h ₁=6400 ~km , ~h ₂=12800 ~km The acceleration due to gravity at height h is g= G M (R+h)^2 g 1 (R+h)^2 g ₂ ~g ₁ = ( R + h ₁ )^2 ( R + h ₂ )^2 = (6400+6400)^2 (6400+12800)^2 = 4 9 g₂= 4 9 g₁= 4 9 2.5=1.11 ~m / s ^2