The escape speed of an object on the surface of the earth is V . If the object is thrown out with speed 4 ~V from the surface of the earth, the speed of the object far away from the earth is

Step-by-step solution

Let V₀ be the speed of object far away from earth. By law of conservation of mechanical energy 1 2 ~m ( UV )^2- GMm R = 1 2 mV ₀^2+0 aligned & 1 2 ~m 16 V ^2- 1 2 ~m 2 GM R = 1 2 mV ₀^2 & 1 2 mV ^2 16- 1 2 mV ^2= 1 2 mV ₀^2 & 15 ~V ^2= V ₀^2 & V ₀= 15 ~V aligned