A uniform solid sphere of radius R produces a gravitational acceleration of a o on its surface. The distance of the point from the centre of the sphere where the gravitational acceleration becomes a o 4 is,

Step-by-step solution

On the surface of the uniform solid sphere, gravitational field(also called gravitational acceleration) is given by, - G M R 2 = a 0 . Gravitational field at any height h is given by, a = a 0 1 + h R - 2 ⇒ a 0 4 = a 0 1 + h R - 2 ⇒ 1 + h R 2 = 4 ⇒ h = R Hence, distance from the centre will be, = R + R = 2 R