AP EAMCET202119 Aug 2021Morning ShiftPhysicsGravitationActual
The acceleration due to gravity at a height ( 1 / 20 ) t h of the radius of earth above the earth's surface is 9 m s - 2 . Its value at an equal depth below the surface of earth is
Options
- A9   m   s − 2
- B9 . 25   m   s − 2
- C9 . 5   m   s − 2
- D9 . 8   m   s − 2
Correct answer
C. 9 . 5   m   s − 2
Step-by-step solution
The variation in acceleration due to gravity due to height above the earth surface is, g ' = g 1 - 2 h R Given that g ' = 9   m   s - 2     and h = 1 20 R   therefore, ⇒ 9 = g 1 - 1 10 ⇒ g = 10   m   s - 2 The variation in acceleration due to gravity due to height below the earth surface is g ' ' = g 1 - h R   Here h = R 20 therefore, g ' ' = 10 1 - 1 20   = 19 2 = 9 . 5   m   s - 2