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AP EAMCET202022 Sep 2020Evening ShiftPhysicsGravitationActual

The period of revolution of planet A around the sun is 8 times that of B . The distance of A from sun is how many times greater than that of B from the sun?

Options

  1. A2
  2. B3
  3. C4
  4. D5

Correct answer

C. 4

Step-by-step solution

If T_A and T_B are the time periods of planet A and B around the sun respectively, then T_A=8 T_B According to Kepler's law, array rlrl & & T^2 & R^3 & ( T_A T_B )^2 & = ( R_A R_B )^3 & & R_A R_B & = ( T_A T_B )^ 2 / 3 = ( 8 T_B T_B )^ 2 / 3 & & =(8)^ 2 / 3 = (2^3 )^ 2 / 3 =2^2 & & R_A R_B & =4 R_A=4 R_B array

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