Two bodies of masses m and 9 m are placed at a distance r . The gravitational potential at a point on the line joining them, where gravitational field is zero, is ( G is universal gravitational constant)

Step-by-step solution

Rom the body of mass m , the distance of the point where gravitational field is zero aligned & x= d m₂ m₁ +1 x= r 9 m m +1 x= 1 4 & Again (r-x)=r- r 4 = 3 r 4 & Potential, v=v₁+v₂ & = G m₂ X - G m₁ r-x =- G m r / 4 - G(9 m) 3 r / 4 & =- 4 G m r - 12 G m r =- 16 G m r aligned