A satellite is launched into a circular orbit of radius R around earth while a second satellite is launched into a orbit of radius 1.02 R . The percentage difference in the time periods of the two satellites is :

Step-by-step solution

From Kepler's law, T^2 R^3 T₁^2 T₂^2 = R₁^3 R₂^3 T₁ T₂ = ( R₁ R₂ )^ 3 / 2 = ( R 1.02 R )^ 3 / 2 T₁ T₂ = ( 50 51 )^ 3 / 2 T₁ T₂ = 50 51 ( 50 51 )^ 1 2 T₁ T₂ = 50 51 0.99 T₁ T₂ = 0.97 1 T₁=0.97 x, T₂=x Difference =T₂-T₁=x-0.97 x=0.03 x % difference = 0.03 x x 100=3 %