AP EAMCET202421 May 2024Morning ShiftPhysicsMagnetic Effects of CurrentActual
A rectangular loop of sides 25 cm and 10 cm carrying a current of 10 A is placed with its longer side parallel to a long straight conductor 10 cm apart carrying current 25 A. The net force on the loop is
Options
- A6.25 10⁻⁵ ~N
- B5.5 10⁻⁵ ~N
- C3.75 10⁻⁵ ~N
- D8.75 10⁻¹¹ ~N
Correct answer
A. 6.25 10⁻⁵ ~N
Step-by-step solution
Due to symmetry, aligned & F ₃= F ₄ & ~F ₁= ₀ I ₁ I ₂ 1 2 r ₁ & ~F ₂= ₀ I ₁ I ₂ 1 2 r ₂ aligned Net force on the loop, aligned & F = ( F ₁- F ₂ )+ ( F ₃- F ₄ ) & = ₀ I ₁ I ₂ 1 2 ( 1 r ₁ - 1 r ₂ ) & = 4 10⁻⁷ 25 10 25 10⁻² 2 ( 1 10 - 1 20 ) 10^2 & =6.25 10⁻⁵ ~N aligned