AP EAMCET202418 May 2024Morning ShiftPhysicsMagnetic Effects of CurrentActual
An electron is moving with a velocity (2 i +3 j ) ms ⁻¹ in an electric field (3 i +6 j +2 k ) Vs ⁻¹ and a magnetic field of (2 j +3 k ) T . Then the magnitude and direction (with x -axis) of the Lorentz force acting on the electron is
Options
- A9.6 10⁻¹⁹ ~N , = ⁻¹ ( 2 5 )
- B9.6 10⁻¹⁹ ~N , = ⁻¹ ( 5 2 )
- C2.15 10⁻¹⁸ ~N , = ⁻¹ ( 2 5 )
- D2.15 10⁻¹⁸ ~N , = ⁻¹ ( 5 3 )
Correct answer
C. 2.15 10⁻¹⁸ ~N , = ⁻¹ ( 2 5 )
Step-by-step solution
v=(2 i +3 j ) m / s , E=(3 i +6 j +2 k ) Vs B =(2 i +3 k ) T The lorentz force acting on electron is aligned & F =- e ( v b )- e E & =- e [(2 i +3 j ) (2 i +3 k )+(3 i +6 j +2 k )] aligned aligned & =-6 e (2 i + k ) & F =6 1.6 10⁻¹⁹ 5 =2.15 10⁻¹⁸ ~N aligned The direction of Lorentz force with x -axis is aligned & = 2 2^2+1^2 = 2 5 & = ⁻¹ ( 2 5 ) aligned