AP EAMCET202317 May 2023Evening ShiftPhysicsMagnetic Effects of CurrentActual
The distance moved by a charged particle along the magnetic field (the component of velocity is parallel to the magnetic field) in one rotation is given by ( m - mass of the particle, v - velocity of the particle, q charge of the particle, B - magnetic field)
Options
- A2 m v q B
- Bmv qB
- C4 mv qB
- D2 m v q B^2
Correct answer
A. 2 m v q B
Step-by-step solution
If the velocity component v _ y is perpendicular to the magnetic field B , the magnetic force acts like a centripetal force qv _ y B . aligned & q v_y B= m_y^2 r & v_y= q B r m & v_y=r & = q B m aligned Time taken for one revolution T = 2 = 2 m qB The distance moved by a changed particle along the magnetic field. aligned & x=V t & = 2 mv q B aligned