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AP EAMCET202317 May 2023Evening ShiftPhysicsMagnetic Effects of CurrentActual

The distance moved by a charged particle along the magnetic field (the component of velocity is parallel to the magnetic field) in one rotation is given by ( m - mass of the particle, v - velocity of the particle, q charge of the particle, B - magnetic field)

Options

  1. A2 m v q B
  2. Bmv qB
  3. C4 mv qB
  4. D2 m v q B^2

Correct answer

A. 2 m v q B

Step-by-step solution

If the velocity component v _ y is perpendicular to the magnetic field B , the magnetic force acts like a centripetal force qv _ y B . aligned & q v_y B= m_y^2 r & v_y= q B r m & v_y=r & = q B m aligned Time taken for one revolution T = 2 = 2 m qB The distance moved by a changed particle along the magnetic field. aligned & x=V t & = 2 mv q B aligned

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