A toroid has a non ferromagnetic core of inner radius 24 cm and outer radius 25 cm , around which 4900 turns of a wire are wound. If the current in the wire is 12 A , the magnetic field inside the core of the toroid is

Step-by-step solution

Here, r 1   =   24   cm = 24 × 10 - 2   m r 2   =   25   cm = 25 × 10 - 2   m N = 4900 turns, I = 12   A Now, r = r 1 + r 2 2 = 24 . 5 × 10 - 2   m Therefore, magnetic field will be B = μ 0 N I 2 πr = 4 π × 10 - 7 4900 12 2 π × 24 . 5 × 10 - 2 = 4800 × 10 - 5 ≈ 48   mT