Figure shows the cross-sectional view of the hollow cylindrical conductor with inner radius R and outer radius 2 R , carrying uniformly distributed current i along its axis. The magnetic induction at point P at a distance 3 R / 2 from the axis of the cylinder will be

Step-by-step solution

The given situation is shown in the following figure, We know that, magnetic field induction at point P is given as aligned B & = ₀ 4 2 i O P [ O P^2-R^2 (2 R)^2-R^2 ] & = ₀ 4 2 i 3 R [ ( 3 R 2 )^2-R^2 4 R^2-R^2 ] & = ₀ i 3 R [ ( 9 R^2 4 )-R^2 3 R^2 ]= ₀ i 3 R [ 5 R^2 12 R^2 ] & = ₀ i 3 R 5 12 = 5 ₀ i 36 R aligned